Let $f:[0,\infty ) \to [0,\infty )$ be defined as $f(x) = \int_0^x {[y]dy}$
where [x] is the greatest integer less than or equal to x. Which of the following is true?
Solution
$f:[0,\infty ) \to [0,\infty ),f(x) = \int_0^x {[y]dy}$<br><br>Let $x = n + f,f \in (0,1)$<br><br>So, $f(x) = 0 + 1 + 2 + ... + (n - 1) + \int\limits_n^{n + f} {n\,dy}$<br><br>$f(x) = {{n(n - 1)} \over 2} + nf$<br><br>$= {{[x]([x] - 1)} \over 2} + [x]\{ x\}$<br><br>Note $$\mathop {\lim }\limits_{x \to {n^ + }} f(x) = {{n(n - 1)} \over 2},\mathop {\lim }\limits_{x \to {n^ - }} f(x) = {{(n - 1)(n - 2)} \over 2} + (n - 1)$$<br><br>$= {{n(n - 1)} \over 2}$<br><br>$f(x) = {{n(n - 1)} \over 2}(n \in {N_0})$<br><br>so f(x) is cont. $\forall$ x $\ge$ 0 nd diff. except at integer points
About this question
Subject: Mathematics · Chapter: Definite Integration · Topic: Properties of Definite Integrals
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