Let f : (a, b) $\to$ R be twice differentiable function such that $f(x) = \int_a^x {g(t)dt}$ for a differentiable function g(x). If f(x) = 0 has exactly five distinct roots in (a, b), then g(x)g'(x) = 0 has at least :
Solution
$f(x) = \int_a^x {g(t)dt}$
<br><br>$\Rightarrow$ f′(x) = g(x)
<br><br>$\Rightarrow$ f′'(x) = g'(x)
<br><br>Given, g(x).g'(x) = 0
<br><br>$\Rightarrow$ f′(x).f′'(x) = 0
<br><br>Also given f(x) has exactly 5 roots.
<br><br>So from Rolle's theorem we can say,
<br><br>f′(x) has 4 roots and f′'(x) has 3 roots.
<br><br>$\therefore$ f′(x).f′'(x) = 0 has 4 + 3 = 7 roots.
About this question
Subject: Mathematics · Chapter: Definite Integration · Topic: Properties of Definite Integrals
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