Easy MCQ +4 / -1 PYQ · JEE Mains 2020

$$\mathop {\lim }\limits_{x \to 0} {{\int_0^x {t\sin \left( {10t} \right)dt} } \over x}$$ is equal to

  1. A $- {1 \over 5}$
  2. B $- {1 \over 10}$
  3. C 0 Correct answer
  4. D ${1 \over 10}$

Solution

$$\mathop {\lim }\limits_{x \to 0} {{\int_0^x {t\sin \left( {10t} \right)dt} } \over x}$$ <br><br>This is in ${0 \over 0}$ form. <br><br>So apply newton leibniz rule <br><br>$\mathop {\lim }\limits_{x \to 0} {{x.\sin \left( {10x} \right) - 0} \over 1}$ = 0

About this question

Subject: Mathematics · Chapter: Definite Integration · Topic: Properties of Definite Integrals

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