If [x] denotes the greatest integer less than or equal to x, then the value of the integral $\int_{ - \pi /2}^{\pi /2} {[[x] - \sin x]dx}$ is equal to :
Solution
$I = \int_{ - \pi /2}^{\pi /2} {[[x] - \sin x]dx}$<br><br>$= \int_{ - \pi /2}^{\pi /2} {\left( {[x] + [ - \sin x]} \right)dx}$<br><br>$= \int_0^{\pi /2} {\left( {[x] + [ - \sin x] + [ - x] + [\sin x]} \right)} dx$<br><br>$= \int_0^{\pi /2} {( - 2)dx}$<br><br>$= - \pi$
About this question
Subject: Mathematics · Chapter: Definite Integration · Topic: Properties of Definite Integrals
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