Let g(x) = $\int_0^x {f(t)dt}$, where f is continuous function in [ 0, 3 ] such that ${1 \over 3}$ $\le$ f(t) $\le$ 1 for all t$\in$ [0, 1] and 0 $\le$ f(t) $\le$ ${1 \over 2}$ for all t$\in$ (1, 3]. The largest possible interval in which g(3) lies is :

Let $f$ be $a$ differentiable function defined on $\left[ {0,{\pi \over 2}} \right]$ such that $f(x) 0$ and $$f(x) + \int_0^x {f(t)\sqrt {1…

Let $f(x) = \int\limits_0^x {{e^t}f(t)dt + {e^x}}$ be a differentiable function for all x$\in$R. Then f(x) equals :

The value of $$\mathop {\lim }\limits_{n \to \infty } {1 \over n}\sum\limits_{j = 1}^n {{{(2j - 1) + 8n} \over {(2j - 1) + 4n}}} $$ is…

If $$\int_\limits{\frac{\pi}{6}}^{\frac{\pi}{3}} \sqrt{1-\sin 2 x} d x=\alpha+\beta \sqrt{2}+\gamma \sqrt{3}$$, where $\alpha, \beta$ and…

$$\lim _\limits{x \rightarrow \frac{\pi}{2}}\left(\frac{\int_{x^3}^{(\pi / 2)^3}\left(\sin \left(2 t^{1 / 3}\right)+\cos \left(t^{1 /…