Let $P Q$ be a chord of the parabola $y^2=12 x$ and the midpoint of $P Q$ be at $(4,1)$. Then, which of the following point lies on the line passing through the points $\mathrm{P}$ and $\mathrm{Q}$ ?
Solution
<p>$y^2=12 x$</p>
<p>Chord $P Q$ having mid-point $(x_1, y_1)=(4,1)$ equation of chord $P Q$</p>
<p>$$\begin{aligned}
& T=S_1 \\
& y y_1-12 \frac{\left(x+x_1\right)}{2}=y_1^2-12 x_1 \\
& y-6(x+4)=1-12 \times 4 \\
& y-6 x-24=-47 \\
& y-6 x+23=0
\end{aligned}$$</p>
<p>From option (4) $x=\frac{1}{2}$ & $y=-20$</p>
<p>$-20-6 \times \frac{1}{2}+23=0$</p>
About this question
Subject: Mathematics · Chapter: Conic Sections · Topic: Parabola
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