Medium MCQ +4 / -1 PYQ · JEE Mains 2022

If $y = {m_1}x + {c_1}$ and $y = {m_2}x + {c_2}$, ${m_1} \ne {m_2}$ are two common tangents of circle ${x^2} + {y^2} = 2$ and parabola y2 = x, then the value of $8|{m_1}{m_2}|$ is equal to :

  1. A $3 + 4\sqrt 2$
  2. B $- 5 + 6\sqrt 2$
  3. C $- 4 + 3\sqrt 2$ Correct answer
  4. D $7 + 6\sqrt 2$

Solution

<p>Let tangent to ${y^2} = x$ be</p> <p>$y = mx + {1 \over {4m}}$</p> <p>For it being tangent to circle.</p> <p>$\left| {{{{1 \over 4}m} \over {\sqrt {1 + {m^2}} }}} \right| = \sqrt 2$</p> <p>$\Rightarrow 32{m^4} + 32{m^2} - 1 = 0$</p> <p>$\Rightarrow {m^2} = {{ - 32 \pm \sqrt {{{(32)}^2} + 4(32)} } \over {64}}$</p> <p>$\Rightarrow 8{m_1}{m_2} = - 4 + 3\sqrt 2$</p>

About this question

Subject: Mathematics · Chapter: Conic Sections · Topic: Parabola

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