Let $\mathrm{H}$ be the hyperbola, whose foci are $(1 \pm \sqrt{2}, 0)$ and eccentricity is $\sqrt{2}$. Then the length of its latus rectum is :
Solution
$ 2 \mathrm{ae}=|(1+\sqrt{2})-(1+\sqrt{2})|=2 \sqrt{2}$
<br/><br/>$\Rightarrow$ $\mathrm{ae}=\sqrt{2}$
<br/><br/>$\Rightarrow$ $\mathrm{a}=1$
<br/><br/>$\Rightarrow \mathrm{b}=1 \because \mathrm{e}=\sqrt{2} \Rightarrow$ Hyperbola is rectangular
<br/><br/>$\Rightarrow \mathrm{L} . \mathrm{R}=\frac{2 \mathrm{~b}^{2}}{\mathrm{a}}=2$
About this question
Subject: Mathematics · Chapter: Conic Sections · Topic: Parabola
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