The centre of the circle passing through the
point (0, 1) and touching the parabola
y = x2 at the point (2, 4) is :
Solution
Circle passes through A(0, 1) and B(2, 4).
<br><br>y = x<sup>2</sup>
<br><br>$\Rightarrow$ ${\left. {{{dy} \over {dx}}} \right|_B}$ = 4
<br><br>tangent at (2,4) is
<br><br>(y – 4) = 4(x – 2)
<br><br>4x – y – 4 = 0
<br><br>Equation of circle
<br><br>(x - 2)<sup>2</sup>
+ (y–4)<sup>2</sup>
+ $\lambda$(4x–y - 4) = 0
<br><br>Passing through (0,1)
<br><br>$\therefore$ 4 + 9 +
$\lambda$(–5) = 0
<br><br>$\Rightarrow$ $\lambda$ = ${{13} \over 5}$
<br><br>$\therefore$ Circle is
<br><br>x<sup>2</sup>– 4x + 4 + y<sup>2</sup>
– 8y + 16 +
${{13} \over 5}$[4x - y - 4] = 0
<br><br>$\Rightarrow$ x<sup>2</sup> + y<sup>2</sup> + $\left( {{{52} \over 5} - 4} \right)$x - $\left( {8 + {{13} \over 5}} \right)$y + 20 - ${{{52} \over 5}}$ = 0
<br><br>$\Rightarrow$ x<sup>2</sup> + y<sup>2</sup> + ${{{32} \over 5}x - {{53} \over 5}y}$ + ${{48} \over 5}$ = 0
<br><br>$\therefore$ Centre is $\left( {{{ - 16} \over 5},{{53} \over {10}}} \right)$
About this question
Subject: Mathematics · Chapter: Conic Sections · Topic: Parabola
This question is part of PrepWiser's free JEE Main question bank. 146 more solved questions on Conic Sections are available — start with the harder ones if your accuracy is >70%.