Let L be a tangent line to the parabola y2 = 4x $-$ 20 at (6, 2). If L is also a tangent to the ellipse ${{{x^2}} \over 2} + {{{y^2}} \over b} = 1$, then the value of b is equal to :
Solution
Parabola y<sup>2</sup> = 4x $-$ 20<br><br>Tangent at P(6, 2) will be <br><br>$2y = 4\left( {{{x + 6} \over 2}} \right) - 20$<br><br>2y = 2x + 12 $-$ 20<br><br>2y = 2x $-$ 8<br><br>y = x $-$ 4<br><br>x $-$ y $-$ 4 = 0 ....... (1)<br><br>This is also tangent to ellipse ${{{x^2}} \over 2} + {{{y^2}} \over b} = 1$<br><br>Apply c<sup>2</sup> = a<sup>2</sup>m<sup>2</sup> + b<sup>2</sup><br><br>($-$4)<sup>2</sup> = (2)(1) + b<br><br>b = 14
About this question
Subject: Mathematics · Chapter: Conic Sections · Topic: Parabola
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