Medium MCQ +4 / -1 PYQ · JEE Mains 2021

A hyperbola passes through the foci of the ellipse ${{{x^2}} \over {25}} + {{{y^2}} \over {16}} = 1$ and its transverse and conjugate axes coincide with major and minor axes of the ellipse, respectively. If the product of their eccentricities is one, then the equation of the hyperbola is :

  1. A ${{{x^2}} \over 9} - {{{y^2}} \over 4} = 1$
  2. B ${{{x^2}} \over 9} - {{{y^2}} \over 16} = 1$ Correct answer
  3. C ${{{x^2}} \over 9} - {{{y^2}} \over 25} = 1$
  4. D x<sup>2</sup> $-$ y<sup>2</sup> = 9

Solution

${e_1} = \sqrt {1 - {{16} \over {25}}} = {3 \over 5}$ foci ($\pm$ae, 0)<br><br>Foci = ($\pm$3, 0)<br><br>Let equation of hyperbola be ${{{x^2}} \over {{A^2}}} - {{{y^2}} \over {{B^2}}} = 1$<br><br>Passes through ($\pm$3, 0)<br><br>A<sup>2</sup> = 9, A = 3, ${e_2} = {5 \over 3}$<br><br>${e_2}^2 = 1 + {{{B^2}} \over {{A^2}}}$<br><br>${{25} \over 9} = 1 + {{{B^2}} \over 9} \Rightarrow {B^2} = 16$ <br><br>Equation of the hyperbola <br><br> ${{{x^2}} \over 9} - {{{y^2}} \over {16}} = 1$

About this question

Subject: Mathematics · Chapter: Conic Sections · Topic: Parabola

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