If the point on the curve y2 = 6x, nearest to the point $\left( {3,{3 \over 2}} \right)$ is ($\alpha$, $\beta$), then 2($\alpha$ + $\beta$) is equal to _____________.
Answer (integer)
9
Solution
Let, $P \equiv \left( {{3 \over 2}{t^2},3t} \right)$ is on the curve.<br><br>Normal at point P<br><br>$tx + y = 3t + {3 \over 2}{t^3}$<br><br>Passes through $\left( {3,{3 \over 2}} \right)$<br><br>$\Rightarrow 3t + {3 \over 2} = 3t + {3 \over 2}{t^3}$<br><br>$\Rightarrow {t^3} = 1 \Rightarrow t = 1$<br><br>$P \equiv \left( {{3 \over 2},3} \right) = (\alpha ,\beta )$ <br><br>$2(\alpha + \beta ) = 2\left( {{3 \over 2} + 3} \right) = 9$
About this question
Subject: Mathematics · Chapter: Conic Sections · Topic: Parabola
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