The equation of the chord, of the ellipse $\frac{x^2}{25}+\frac{y^2}{16}=1$, whose mid-point is $(3,1)$ is :
Solution
<p>$$\begin{aligned}
&\text { Equation of chord with given middle point }\\
&\begin{aligned}
& \mathrm{T}=\mathrm{S}_1 \\
& \Rightarrow \frac{3 \mathrm{x}}{25}+\frac{\mathrm{y}}{16}-1=\frac{9}{25}+\frac{1}{16}-1 \\
& 48 \mathrm{x}+25 \mathrm{y}=144+25 \\
& 48 \mathrm{x}+25 \mathrm{y}=169 \text { Ans. }
\end{aligned}
\end{aligned}$$</p>
About this question
Subject: Mathematics · Chapter: Conic Sections · Topic: Parabola
This question is part of PrepWiser's free JEE Main question bank. 146 more solved questions on Conic Sections are available — start with the harder ones if your accuracy is >70%.