Medium MCQ +4 / -1 PYQ · JEE Mains 2025

The equation of the chord, of the ellipse $\frac{x^2}{25}+\frac{y^2}{16}=1$, whose mid-point is $(3,1)$ is :

  1. A $5 x+16 y=31$
  2. B $48 x+25 y=169$ Correct answer
  3. C $4 x+122 y=134$
  4. D $25 x+101 y=176$

Solution

<p>$$\begin{aligned} &\text { Equation of chord with given middle point }\\ &\begin{aligned} & \mathrm{T}=\mathrm{S}_1 \\ & \Rightarrow \frac{3 \mathrm{x}}{25}+\frac{\mathrm{y}}{16}-1=\frac{9}{25}+\frac{1}{16}-1 \\ & 48 \mathrm{x}+25 \mathrm{y}=144+25 \\ & 48 \mathrm{x}+25 \mathrm{y}=169 \text { Ans. } \end{aligned} \end{aligned}$$</p>

About this question

Subject: Mathematics · Chapter: Conic Sections · Topic: Parabola

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