If the three normals drawn to the parabola, y2 = 2x pass through the point (a, 0) a $\ne$ 0, then 'a' must be greater than :
Solution
Let the equation of the normal is <br><br>y = mx $-$ 2am $-$ am<sup>3</sup><br><br>here 4a = 2 $\Rightarrow$ a = ${1 \over 2}$<br><br>y = mx $-$ m $-$ ${1 \over 2}$m<sup>3</sup><br><br>It passing through A(a, 0) then<br><br>0 = am $-$ m $-$ ${1 \over 2}$m<sup>3</sup><br><br>m = 0, a $-$ 1 $-$ ${1 \over 2}$m<sup>2</sup> = 0<br><br>m<sup>2</sup> = 2(a $-$ 1) > 0<br><br>$\Rightarrow$ a > 1
About this question
Subject: Mathematics · Chapter: Conic Sections · Topic: Parabola
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