Remainder when $64^{32^{32}}$ is divided by 9 is equal to ________.
Answer (integer)
1
Solution
<p>Let $32^{32}=\mathrm{t}$</p>
<p>$$\begin{aligned}
& 64^{32^{32}}=64^t=8^{2 t}=(9-1)^{2 t} \\
& =9 \mathrm{k}+1
\end{aligned}$$</p>
<p>Hence remainder $=1$</p>
About this question
Subject: Mathematics · Chapter: Binomial Theorem · Topic: Binomial Expansion
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