The remainder when $\left((64)^{(64)}\right)^{(64)}$ is divided by 7 is equal to
Solution
<p>$$\begin{aligned}
&\begin{aligned}
& 64^{64} \Rightarrow(63+1)^{64}=63 \lambda+1 \\
& 64^{664^{64}} \Rightarrow(63+1)^{64^{64}} \\
& 63 \lambda_1+1
\end{aligned}\\
&\text { Required remainder when divided } 7 \text { is } 1 \text {. }
\end{aligned}$$</p>
About this question
Subject: Mathematics · Chapter: Binomial Theorem · Topic: Binomial Expansion
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