If ${{}^{20}{C_r}}$ is the co-efficient of xr in the expansion of (1 + x)20, then the value of $\sum\limits_{r = 0}^{20} {{r^2}.{}^{20}{C_r}}$ is equal to :
Solution
$\sum\limits_{r = 0}^{20} {{r^2}.{}^{20}{C_r}}$<br><br>$\sum {(4(r - 1) + r).{}^{20}{C_r}}$<br><br>$$\sum {r(r - 1).{{20 \times 19} \over {r(r - 1)}}} .{}^{18}{C_r} + r.{{20} \over r}.\sum {{}^{19}{C_{r - 1}}} $$<br><br>$\Rightarrow 20 \times {19.2^{18}} + {20.2^{19}}$<br><br>$\Rightarrow 420 \times {2^{18}}$
About this question
Subject: Mathematics · Chapter: Binomial Theorem · Topic: Applications of Binomial Theorem
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