As per Hardy-Schulze formulation, the flocculation values of the following for ferric hydroxide sol are in the order :
Solution
Since, Fe(OH)<sub>3</sub> is positively charged sol, hence,
anionic charge will flocculate.
<br><br>As per Hardy Schulze rules coagulation power
of anion follows the order :
<br><br>Fe(CN)<sub>6</sub><sup>3–</sup> $>$ CrO<sub>4</sub><sup>2–</sup> $>$ Cl<sup>–</sup> = Br<sup>–</sup><sup></sup> = NO<sub>3</sub><sub></sub><sup>–</sup>
<br><br>Higher the coagulation power lower will be its
flocculation value
therefore order will be :
<br><br>Fe(CN)<sub>6</sub><sup>3–</sup> $<$ CrO<sub>4</sub><sup>2–</sup> $<$ Cl<sup>–</sup> = Br<sup>–</sup><sup></sup> = NO<sub>3</sub><sub></sub><sup>–</sup>
About this question
Subject: Chemistry · Chapter: Surface Chemistry · Topic: Adsorption
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