Four gases A, B, C and D have critical temperatures $5.3,33.2,126.0$ and $154.3 \mathrm{~K}$ respectively. For their adsorption on a fixed amount of charcoal, the correct order is:
Solution
<p>The extent of adsorption of a gas on a solid surface depends on the critical temperature of the gas and the temperature of the solid surface. The critical temperature is the temperature above which a gas cannot be liquefied, no matter how much pressure is applied. Therefore, gases with higher critical temperatures are less likely to be adsorbed on a solid surface than gases with lower critical temperatures.</p>
<p>In this case, the gases are A, B, C, and D, with critical temperatures of 5.3 K, 33.2 K, 126.0 K, and 154.3 K, respectively. Therefore, the correct order of adsorption on a fixed amount of charcoal is:</p>
<p>D > C > B > A</p>
About this question
Subject: Chemistry · Chapter: Surface Chemistry · Topic: Adsorption
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