The graph of $\log \frac{x}{m}$ vs $\log \mathrm{p}$ for an adsorption process is a straight line inclined at an angle of $45^{\circ}$ with intercept equal to $0.6020$. The mass of gas adsorbed per unit mass of adsorbent at the pressure of $0.4 \mathrm{~atm}$ is _________ $\times 10^{-1}$ (Nearest integer).
Given: $\log 2=0.3010$
Answer (integer)
16
Solution
<p>$\mathrm{{1 \over n} = \tan (45^\circ )}$</p>
<p>$\therefore$ $\mathrm{n = 1}$</p>
<p>$\mathrm{\log k = 0.602}$</p>
<p>$\therefore$ $\mathrm{k = 4}$</p>
<p>$\mathrm{{x \over m} = k.{p^{1/n}}}$</p>
<p>$= 4 \times 0.4 = 1.6$ g</p>
About this question
Subject: Chemistry · Chapter: Surface Chemistry · Topic: Adsorption
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