Match List - I with List - II.
| List - I Reaction |
List - II Catalyst |
||
|---|---|---|---|
| (A) | $4N{H_3}(g) + 5{O_2}(g) \to 4NO(g) + 6{H_2}O(g)$ | (I) | $NO(g)$ |
| (B) | ${N_2}(g) + 3{H_2}(g) \to 2N{H_3}(g)$ | (II) | ${H_2}S{O_4}(l)$ |
| (C) | $${C_{12}}{H_{22}}{O_{11}}(aq) + {H_2}O(l) \to \mathop {{C_6}{H_{12}}{O_6}}\limits_{Glu\cos e} + \mathop {{C_6}{H_{12}}{O_6}}\limits_{Fructose} $$ | (III) | $Pt(s)$ |
| (D) | $2S{O_2}(g) + {O_2}(g) \to 2S{O_3}(g)$ | (IV) | $Fe(s)$ |
Choose the correct answer from the options given below :
Solution
(A) $4 \mathrm{NH}_{3}(\mathrm{~g})+5 \mathrm{O}_{2}(\mathrm{~g}) \stackrel{\mathrm{Pt}(\mathrm{s})}{\longrightarrow} 4 \mathrm{NO}(\mathrm{g})+6 \mathrm{H}_{2} \mathrm{O}(\mathrm{g})$
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(B) $\mathrm{N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}(\mathrm{~g}) \stackrel{\mathrm{Fe}(\mathrm{s})}{\longrightarrow} 2 \mathrm{NH}_{3}(\mathrm{~g})$
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(C) $\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\mathrm{l}) \stackrel{\mathrm{H}_{2} \mathrm{SO}_{4}(\mathrm{l})}{\longrightarrow}$ $\underset{\text { Glucose }}{\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}}+\underset{\text { Fructose }}{\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}}$
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(D) $2 \mathrm{SO}_{2}(\mathrm{~g})+\mathrm{O}_{2}(\mathrm{~g}) \stackrel{\mathrm{NO}(\mathrm{g})}{\longrightarrow} 2 \mathrm{SO}_{3}$
About this question
Subject: Chemistry · Chapter: Surface Chemistry · Topic: Adsorption
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