The mass of gas adsorbed, x, per unit mass of
adsorbate, m, was measured at various pressures,
p. A graph between $\log {x \over m}$
and log p gives a
straight line with slope equal to 2 and the intercept
equal to 0.4771. The value of
${x \over m}$
at a pressure of
4 atm is :
(Given log 3 = 0.4771)
Answer (integer)
48
Solution
According to Freundlich adsorption isotherm, in the median range of pressure
<br><br> ${x \over m} \propto {P^{{1 \over n}}}$
<br><br>$\Rightarrow$ ${x \over m}$ = kP$^{{1 \over n}}$ ....(1)
<br><br>taking log both sides, we get,
<br><br>log${x \over m}$ = logk + ${1 \over n}$ logP
<br><br>Here in graph between log${x \over m}$ and logP,
slope is ${1 \over n}$ and intercepts = log k.
<br><br>Given, log k = 0.4771 $\Rightarrow$ k = 3
<br><br>Slope ${1 \over n}$ = 2
<br><br>put in eq. (1), ${x \over m}$ = 3 $\times$ (4)<sup>2</sup> = 48
About this question
Subject: Chemistry · Chapter: Surface Chemistry · Topic: Adsorption
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