Medium MCQ +4 / -1 PYQ · JEE Mains 2020

A diatomic molecule X2 has a body-centred cubic (bcc) structure with a cell edge of 300 pm. The density of the molecule is 6.17 g cm–3. The number of molecules present in 200 g of X2 is :
(Avogadro constant (N A) = 6 $\times$ 1023 mol–1 )

  1. A 8 N<sub>A</sub>
  2. B 40 N<sub>A</sub>
  3. C 4 N<sub>A</sub> Correct answer
  4. D 2 N<sub>A</sub>

Solution

d = ${{Z \times M} \over {{a^3} \times {N_A}}}$ <br><br>$\Rightarrow$ 6.17 = $${{2 \times M} \over {{{\left( {3 \times {{10}^{ - 8}}} \right)}^3} \times 6 \times {{10}^{23}}}}$$ [For BCC Z = 2] <br><br>$\Rightarrow$ M = 50 g/mol <br><br>Number of moles in 200 gm = ${{{200} \over {50}}}$ = 4 <br><br>$\therefore$ Number of molecules = 4$\times$N<sub>A</sub>

About this question

Subject: Chemistry · Chapter: States of Matter · Topic: Gas Laws

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