Atoms of element X form hcp lattice and those of element Y occupy ${2 \over 3}$ of its tetrahedral voids. The percentage of element X in the lattice is ____________. (Nearest integer)
Answer (integer)
43
Solution
Since $X$ occupies hop lattice,
Number of particles of type $X$ in a unit cell $=6$
<br/><br/>
Number of particles of type $Y=\frac{2}{3} \times 12=8$
<br/><br/>
$\therefore$ Percentage of element $X=\frac{6}{14} \times 100$
<br/><br/>
$$
\begin{aligned}
&=\frac{300}{7} \\\\
&=42.85 \\\\
&\simeq 43 \%
\end{aligned}
$$
About this question
Subject: Chemistry · Chapter: States of Matter · Topic: Gas Laws
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