Easy MCQ +4 / -1 PYQ · JEE Mains 2024

A solution of two miscible liquids showing negative deviation from Raoult's law will have :

  1. A increased vapour pressure, increased boiling point
  2. B increased vapour pressure, decreased boiling point
  3. C decreased vapour pressure, decreased boiling point
  4. D decreased vapour pressure, increased boiling point Correct answer

Solution

<strong>Negative Deviation from Raoult's Law</strong> <br/><br/><ul> <li>Negative deviation means the intermolecular forces of attraction between the molecules of the two liquids (A-B) are stronger than the forces between molecules of the pure liquids (A-A and B-B).</li> <br/><li>This stronger attraction makes it harder for molecules to escape into the vapor phase.</li> </ul> <br/><br/><strong>Effect on Vapor Pressure and Boiling Point</strong> <br/><br/><ul> <li><strong>Vapor Pressure :</strong> Since the molecules are held more tightly, the vapor pressure of the solution will be lower than expected from Raoult's law. <strong>Decreased vapor pressure</strong>.</li><br> <li><strong>Boiling Point :</strong> A lower vapor pressure means you need to increase the temperature further to reach atmospheric pressure, where boiling occurs. Therefore, the boiling point of the solution will be higher than expected. <strong>Increased boiling point</strong>.</li> </ul> <br/><strong>Answer</strong> <p>The correct answer is <strong>Option D: decreased vapor pressure, increased boiling point</strong>.</p> <p></p>

About this question

Subject: Chemistry · Chapter: States of Matter · Topic: Gas Laws

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