"If 250 cm3 of an aqueous solution containing 0.73 g of a protein A is isotonic with one litre of another aqueous solution containing 1.65 g of a protein B, at 298 K, the ratio of the molecular masses of A and B is ______ × 10–2 (to the nearest integer)."

Question

Accepted Answer

"Let molar mass of protein A = x g/mol

Let molar mass of protein B = y g/mol

$\pi$_A = osmotic pressure of protein A = ${{0.73} \over x} \times {{1000} \over {250}} \times RT$

$\pi$_B = osmotic pressure of protein B = ${{1.65} \over y} \times {1 \over 1} \times RT$

Given $\pi$_A = $\pi$_B

$\Rightarrow$ ${{0.73} \over x} \times {{1000} \over {250}} \times RT$ = ${{1.65} \over y} \times {1 \over 1} \times RT$

$\Rightarrow$ ${x \over y}$ = ${{0.73} \over {0.25 \times 1.65}}$ = 1.77

= 177 $\times$ 10^-2"

If 250 cm³ of an aqueous solution containing 0.73 g of a protein A is isotonic with one litre of another aqueous solution containing 1.65 g of a protein B, at 298 K, the ratio of the molecular masses of A and B is ______ × 10^–2 (to the nearest integer).

Solution

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If 250 cm3 of an aqueous solution containing 0.73 g of a protein A is isotonic with one litre of another aqueous solution containing 1.65 g of a protein B, at 298 K, the ratio of the molecular masses of A and B is ______ × 10–2 (to the nearest integer).

Solution

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If 250 cm³ of an aqueous solution containing 0.73 g of a protein A is isotonic with one litre of another aqueous solution containing 1.65 g of a protein B, at 298 K, the ratio of the molecular masses of A and B is ______ × 10^–2 (to the nearest integer).