The elevation in boiling point for 1 molal solution of non-volatile solute A is $3 \mathrm{~K}$. The depression in freezing point for 2 molal solution of $\mathrm{A}$ in the same solvent is 6 $K$. The ratio of $K_{b}$ and $K_{f}$ i.e., $K_{b} / K_{f}$ is $1: X$. The value of $X$ is [nearest integer]
Answer (integer)
1
Solution
Molality of a solution of non volatile solute $(A)=1$<br/><br/> Elevation in boiling point is given by
<br/><br/>
$\Delta \mathrm{T}_{\mathrm{b}}=\mathrm{K}_{\mathrm{b}} \mathrm{m}$
<br/><br/>
$3=\mathrm{K}_{\mathrm{b}} \times 1$ ... (1)<br/><br/>
Molality of $(A)$ in the same solvent $=2$
<br/><br/>
Depression in freezing point is given by
<br/><br/>
$$
\begin{aligned}
&\Delta \mathrm{T}_{\mathrm{f}}=\mathrm{K}_{\mathrm{f}} \mathrm{m} \\
&6=\mathrm{K}_{\mathrm{f}} \times 2 \quad\quad\quad{...(2)} \\
&\text { Dividing (1) by (2) } \\
&\frac{\mathrm{K}_{\mathrm{b}}}{\mathrm{K}_{\mathrm{f}}}=\frac{1}{\mathrm{X}}=\frac{1}{1} \\
&\therefore \quad \mathrm{X}=1
\end{aligned}
$$
About this question
Subject: Chemistry · Chapter: States of Matter · Topic: Gas Laws
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