When 3.00 g of a substance 'X' is dissolved in 100 g of CCl4, it raises the boiling point by 0.60 K. The molar mass of the substance 'X' is ______________ g mol$-$1. (Nearest integer).
[Given Kb for CCl4 is 5.0 K kg mol$-$1]
Answer (integer)
250
Solution
$\Delta$T<sub>b</sub> = K<sub>b</sub> $\times$ molality<br><br>0.60 = 5 $\times$ $\left( {{{3/M} \over {100/100}}} \right)$<br><br>M = 250
About this question
Subject: Chemistry · Chapter: States of Matter · Topic: Gas Laws
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