In a binary compound, atoms of element A form a hcp structure and those of element M occupy 2/3 of the tetrahedral voids of the hcp structure. The formula of the binary compound is :
Solution
In HCP unit cell,<br><br>Z = 6 so A = 6<br><br>Also we know, in HCP<br><br>Tetrahedral voids = 2Z = 12<br><br>$\therefore$ No. of M = ${2 \over 3}$ [TV] = ${2 \over 3}$ $\times$ 12 = 8<br><br>$\therefore$ Formula = M<sub>8</sub>A<sub>6</sub> = M<sub>4</sub>A<sub>3</sub>
About this question
Subject: Chemistry · Chapter: States of Matter · Topic: Gas Laws
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