A metal M forms hexagonal close-packed structure. The total number of voids in 0.02 mol of it is _________ $\times$ $10^{21}$ (Nearest integer).
(Given $\mathrm{N_A=6.02\times10^{23}}$)
Answer (integer)
36
Solution
<p>Number of voids</p>
<p>$=0.02\times3\times6.02\times10^{23}$</p>
<p>$\simeq36\times10^{21}$</p>
About this question
Subject: Chemistry · Chapter: States of Matter · Topic: Gas Laws
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