Two solutions A and B are prepared by dissolving 1 g of non-volatile solutes X and Y, respectively in 1 kg of water. The ratio of depression in freezing points for A and B is found to be 1 : 4. The ratio of molar masses of X and Y is
Solution
$\Delta T_{f}=i k_{f} \times m$
<br/><br/>
$$
\frac{\Delta T_{\mathrm{f}(\mathrm{A})}}{\Delta \mathrm{T}_{\mathrm{f}(\mathrm{B})}}=\frac{1}{4}
$$
<br/><br/>
$$\frac{\mathrm{i} \times \mathrm{K}_{\mathrm{f}} \times \frac{1}{\mathrm{M}_{\mathrm{A}}} \times 1}{\mathrm{i} \times \mathrm{K}_{\mathrm{f}} \times \frac{1}{\mathrm{M}_{\mathrm{B}}} \times 1}=\frac{1}{4}$$
<br/><br/>
$\frac{M_{B}}{M_{A}}=\frac{1}{4}$
<br/><br/>
$M_{A}: M_{B}=4: 1$
About this question
Subject: Chemistry · Chapter: States of Matter · Topic: Gas Laws
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