The oxidation states of 'P' in H4P2O7, H4P2O5 and H4P2O6, respectively, are :
Solution
Oxidation state of P in H<sub>4</sub>P<sub>2</sub>O<sub>7</sub>, H<sub>4</sub>P<sub>2</sub>O<sub>5</sub> and H<sub>4</sub>P<sub>2</sub>O<sub>6</sub> is 5, 3 & 4 respectively<br><br>H<sub>4</sub>P<sub>2</sub>O<sub>7</sub><br><br>2x + 4(+ 1) + 7 ($-$2) = 0<br><br>x = + 5<br><br>${H_4}\underline {{P_2}} {O_5}$<br><br>2x + 4(+ 1) + 5 ($-$2) = 0<br><br>x = + 3<br><br>${H_4}\underline {{P_2}} {O_6}$<br><br>2x + 4 (+ 1) + 6($-$2) = 0<br><br>x = +4
About this question
Subject: Chemistry · Chapter: Redox Reactions · Topic: Oxidation States
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