The volume, in mL, of 0.02 M K2Cr2O7 solution
required to react with 0.288 g of ferrous
oxalate in acidic medium is _______.
(Molar mass of Fe = 56 g mol–1)
Answer (integer)
50
Solution
K<sub>2</sub>Cr<sub>2</sub>O<sub>7</sub> + FeC<sub>2</sub>O<sub>4</sub> $\to$ Cr<sup>+3</sup> + Fe<sup>+3</sup> + CO<sub>2</sub>
<br><br>n<sub>factor</sub> of K<sub>2</sub>Cr<sub>2</sub>O<sub>7</sub> = 3 $\times$ 2 = 6
<br><br>n<sub>factor</sub> of FeC<sub>2</sub>O<sub>4</sub> = 1 + 2 = 3
<br><br>m. eq. of K<sub>2</sub>Cr<sub>2</sub>O<sub>7</sub> = m. eq. of FeC<sub>2</sub>O<sub>4</sub>
<br><br>$\Rightarrow$ ${{6 \times 0.02 \times vol} \over {1000}}$ = ${{0.288} \over {144}} \times 3$
<br><br>$\Rightarrow$ vol = 50 ml
About this question
Subject: Chemistry · Chapter: Redox Reactions · Topic: Oxidation States
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