"0.01 M KMnO4 solution was added to 20.0 mL of 0.05 M Mohr's salt solution through a burette. The initial reading of 50 mL burette is zero. The volume of KMnO4 solution left in the burette after the end point is _____________ mL. (nearest integer)"

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Accepted Answer

"Meq of oxidizing agent $=$ Meq of reducing agent

$\left(\mathrm{M} \times \mathrm{V} \times \mathrm{n}_{\text{F}}\right)_{\mathrm{KMnO}_{4}}=\left(\mathrm{M} \times \mathrm{V} \times \mathrm{n}_{\text{F}}\right)_{\text {Mohr's salt }}$

$0.01 \times 20 \times 5=0.05 \times V \times 1$

Volume required $=20 ~ \mathrm{ml}$

Since initial volume of $\mathrm{KMnO}_{4}$ in burette is $50 ~\mathrm{ml}$.

Hence volume of $\mathrm{KMnO}_{4}$ left in the burette after end point is $30 ~\mathrm{ml}$."

0.01 M KMnO₄ solution was added to 20.0 mL of 0.05 M Mohr's salt solution through a burette. The initial reading of 50 mL burette is zero. The volume of KMnO₄ solution left in the burette after the end point is _____________ mL. (nearest integer)

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0.01 M KMnO4 solution was added to 20.0 mL of 0.05 M Mohr's salt solution through a burette. The initial reading of 50 mL burette is zero. The volume of KMnO4 solution left in the burette after the end point is _____________ mL. (nearest integer)

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0.01 M KMnO₄ solution was added to 20.0 mL of 0.05 M Mohr's salt solution through a burette. The initial reading of 50 mL burette is zero. The volume of KMnO₄ solution left in the burette after the end point is _____________ mL. (nearest integer)