10.0 mL of 0.05 M KMnO4 solution was consumed in a titration with 10.0 mL of given oxalic acid dihydrate solution. The strength of given oxalic acid solution is _________ $\times$ 10$-$2 g/L.
(Round off to the nearest integer)
Answer (integer)
1575
Solution
n<sub>eq</sub> KMnO<sub>4</sub> = n<sub>eq</sub> H<sub>2</sub>C<sub>2</sub>O<sub>4</sub> . 2H<sub>2</sub>O<br><br>or, ${{10 \times 0.05} \over {1000}} \times 5 = {{10 \times M} \over {1000}} \times 2$<br><br>$\therefore$ Conc. of oxalic acid solution = 0.125 M<br><br>= 0.125 $\times$ 125 g/L = 15.75 g/L<br><br>= 1575 $\times$ 10<sup>$-$2</sup> g/L
About this question
Subject: Chemistry · Chapter: Redox Reactions · Topic: Oxidation States
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