Dichromate ion is treated with base, the oxidation number of Cr in the product formed is ___________.
Answer (integer)
6
Solution
$C{r_2}O_7^{2 - } + 2O{H^ - }$ ⇌ $2CrO_4^{2 - } + {H_2}O$
<br><br>Let Oxidation state of Cr in $CrO_4^{2 - }$ is = x.
<br><br>$\therefore$ x + (–2 × 4) = –2
<br><br>$\Rightarrow$ x = 6
About this question
Subject: Chemistry · Chapter: Redox Reactions · Topic: Oxidation States
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