"The correct order of the ionic radii of O2–, N3–, F– , Mg2+, Na+ and Al3+ is :"

"For isoelectronic species, as the no. of protons\nincreases, size of ions decreases.\n $\\therefore$ Correct order of size for isoelectronic species\n Al 3+ < Mg 2+ < Na + < F – \n < O 2– < N 3– "

Easy MCQ +4 / -1 PYQ · JEE Mains 2020

The correct order of the ionic radii of
O^2–, N^3–, F^– , Mg²⁺, Na⁺ and Al³⁺ is :

A N3– < O2– < F– < Na+ < Mg2+ < Al3+
B N3– < F– < O2– < Mg2+ < Na+ < Al3+
C Al3+ < Na+ < Mg2+ < O2– < F– < N3–
D Al3+ < Mg2+ < Na+ < F– < O2– < N3– Correct answer

Solution

For isoelectronic species, as the no. of protons increases, size of ions decreases. $\therefore$ Correct order of size for isoelectronic species Al3+ < Mg2+ < Na+ < F– < O2– < N3–

About this question

Subject: Chemistry · Chapter: Periodic Table and Periodicity · Topic: Periodic Trends

This question is part of PrepWiser's free JEE Main question bank. 131 more solved questions on Periodic Table and Periodicity are available — start with the harder ones if your accuracy is >70%.

The correct order of the ionic radii of O2–, N3–, F– , Mg2+, Na+ and Al3+ is :

Solution

About this question

More Periodic Table and Periodicity questions

Drill 25 more like these. Every day. Free.

The correct order of the ionic radii of
O^2–, N^3–, F^– , Mg²⁺, Na⁺ and Al³⁺ is :