Match List I with List II
| LIST I (Element) |
LIST II (Electronic Configuration) |
||
|---|---|---|---|
| A. | $\mathrm{N}$ | I. | $[\mathrm{Ar}] 3 \mathrm{~d}^{10} 4 \mathrm{~s}^2 4 \mathrm{p}^5$ |
| B. | $\mathrm{S}$ | II. | $[\mathrm{Ne}] 3 \mathrm{~s}^2 3 \mathrm{p}^4$ |
| C. | $\mathrm{Br}$ | III. | $[\mathrm{He}] 2 \mathrm{~s}^2 2 \mathrm{p}^3$ |
| D. | $\mathrm{Kr}$ | IV. | $[\mathrm{Ar}] 3 \mathrm{~d}^{10} 4 \mathrm{~s}^2 4 \mathrm{p}^6$ |
Choose the correct answer from the options given below:
Solution
<p>To match each element with its correct electronic configuration, let's consider the electronic configurations of each element based on their positions in the periodic table:</p>
<ul>
<li><b>Nitrogen (N)</b>: It is in the 2nd period and belongs to the p-block, specifically group 15. The electronic configuration of nitrogen is $1\text{s}^2 2\text{s}^2 2\text{p}^3$. Looking at the options in List II, this matches with the electronic configuration labeled 'III' ($[\mathrm{He}] 2 \mathrm{s}^2 2 \mathrm{p}^3$), which reflects the electronic configuration of nitrogen starting after the helium core.</li>
<br/><li><b>Sulfur (S)</b>: Sulfur is in the 3rd period, also in the p-block, specifically group 16. Its electronic configuration is $1\text{s}^2 2\text{s}^2 2\text{p}^6 3\text{s}^2 3\text{p}^4$. In the given list, this corresponds to 'II' ($[\mathrm{Ne}] 3 \mathrm{s}^2 3 \mathrm{p}^4$), which captures the configuration of sulfur starting after the neon core.</li>
<br/><li><b>Bromine (Br)</b>: Bromine is located in the 4th period and in the p-block, belonging to group 17. Its electronic configuration is $$1\text{s}^2 2\text{s}^2 2\text{p}^6 3\text{s}^2 3\text{p}^6 3\text{d}^{10} 4\text{s}^2 4\text{p}^5$$, which is correctly represented by 'I' ($[\mathrm{Ar}] 3 \mathrm{d}^{10} 4 \mathrm{s}^2 4 \mathrm{p}^5$), showing the configuration after the argon core.</li>
<br/><li><b>Krypton (Kr)</b>: Krypton falls in the 4th period and is a noble gas situated in the p-block at group 18. Its electronic configuration is $$1\text{s}^2 2\text{s}^2 2\text{p}^6 3\text{s}^2 3\text{p}^6 3\text{d}^{10} 4\text{s}^2 4\text{p}^6$$, which aligns with 'IV' ($[\mathrm{Ar}] 3 \mathrm{d}^{10} 4 \mathrm{s}^2 4 \mathrm{p}^6$), clearly depicting krypton's electronic configuration post-argon.</li>
</ul>
<p>Therefore, the correct match is:</p>
<ol>
<li>A-III (Nitrogen matches with $[\mathrm{He}] 2 \mathrm{s}^2 2 \mathrm{p}^3$)</li>
<li>B-II (Sulfur matches with $[\mathrm{Ne}] 3 \mathrm{s}^2 3 \mathrm{p}^4$)</li>
<li>C-I (Bromine matches with $[\mathrm{Ar}] 3 \mathrm{d}^{10} 4 \mathrm{s}^2 4 \mathrm{p}^5$)</li>
<li>D-IV (Krypton matches with $[\mathrm{Ar}] 3 \mathrm{d}^{10} 4 \mathrm{s}^2 4 \mathrm{p}^6$)</li>
</ol>
<p>Thus, the correct answer is <b>Option C</b>: A-III, B-II, C-I, D-IV.</p>
About this question
Subject: Chemistry · Chapter: Periodic Table and Periodicity · Topic: Periodic Trends
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