Medium MCQ +4 / -1 PYQ · JEE Mains 2025

An element ‘E’ has the ionisation enthalpy value of 374 kJ mol⁻¹. ‘E’ reacts with elements A, B, C and D with electron gain enthalpy values of −328, −349, −325 and −295 kJ mol⁻¹, respectively. The correct order of the products EA, EB, EC and ED in terms of ionic character is :

  1. A <p>EB > EA > EC > ED</p> Correct answer
  2. B <p>EA > EB > EC > ED</p>
  3. C <p>ED > EC > EA > EB</p>
  4. D <p>ED > EC > EB > EA</p>

Solution

<p>Element $E \rightarrow$ Ionisation enthalpy value $\rightarrow 374 \mathrm{~kJ} \mathrm{~mol}^{-1}$</p> <p>Element $A \rightarrow$ Electron gain enthalpy value $\rightarrow-328 \mathrm{~kJ} \mathrm{~mol}^{-1}$</p> Element $B \rightarrow$ Electron gain enthalpy value $\rightarrow-349 \mathrm{~kJ} \mathrm{~mol}^{-1}$</p> <p>Element $C \rightarrow$ Electron gain enthalpy value $\rightarrow-325 \mathrm{~kJ} \mathrm{~mol}{ }^{-1}$</p> <p>Element $D \rightarrow$ Electron gain enthalpy value $\rightarrow-295 \mathrm{~kJ} \mathrm{~mol}^{-1}$</p> <p>Ionization enthalpy is the energy required to remove an election from an atom or ion in the gas phase. An element with lower ionization enthalpy indicate easier cation formation and this lead to higher ionic character. Electron gain enthalpy is the energy released when an election is added to an atom or ion in the gas phase. A highly negative election gain enthalpy Indicate that the atom readily gains electrons, favouring the formation of anions. This leads to stronger ionic character in compounds. High ionic character generally occurs when the difference in ionisation enthalpy and electron gain enthalpy between the two atoms is large.</p> <p>For $E A$,</p> <p>Difference between ionisation enthalpy and electron gain enthalpy</p> <p>$$\begin{aligned} & =374 \mathrm{kJmol}^{-1}-\left(-328 \mathrm{~kJ} \mathrm{~mol}^{-1}\right) \\ & =702 \mathrm{~kJ} \mathrm{~mol}^{-1} \end{aligned}$$</p> <p>For $E B$,</p> <p>$$\begin{aligned} &\text {Difference between ionisation enthalpy and elation gain enthalpy } \\ & =374 \mathrm{~kJ} \mathrm{~mol}^{-1}-\left(-349 \mathrm{~kJ~mol}^1\right) \\ & =723 \mathrm{~kJ} \mathrm{~mol}^{-1} \end{aligned}$$</p> <p>For $E C$,</p> <p>$\begin{aligned} & \text { Difference between ionisation enthalpy and election gain enthalpy } \\ & =374 \mathrm{~kJ} \mathrm{~mol}^{-1}-\left(-325 \mathrm{~kJ} \mathrm{~mol}^{-1}\right) \\ & =699 \mathrm{~kJ} \mathrm{~mol}^{-1}\end{aligned}$</p> <p>For $ED$,</p> Difference between ionisation enthalpy and election gain enthalpy</p> <p>$$\begin{aligned} & =374 \mathrm{~kJ} \mathrm{~mol}^{-1}-\left(-295 \mathrm{~kJ} \mathrm{~mol}^{-1}\right) \\ & =669 \mathrm{~kJ} \mathrm{~mol}^{-1} \end{aligned}$$</p> <p>Higher difference between ionisation enthalpy and election gain enthalpy is for compound EB. So, EB has higher ionic character.</p> <p>The Lower value of difference between ionisation enthalpy and election gain enthalpy is for compound ED. So, ED has lower ionic character. The increasing order of compounds for the difference between ionisation enthalpy and electron gain enthalpy $\to$</p> <p>$E B< E C < E A< E B$</p> <p>So, increasing. order of compounds for ionic character:</p> <p>$E D< E C < E A< E B$</p> <p>In the decreasing order,</p> <p>$E B>E A>E C>E D$</p> <p>Correct option (1)</p>

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Subject: Chemistry · Chapter: Periodic Table and Periodicity · Topic: Periodic Trends

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