Electronic configuration of four elements A, B, C and D are given below :

(A) $1 s^2 2 s^2 2 p^3$

(B) $1 s^2 2 s^2 2 p^4$

(C) $1 s^2 2 s^2 2 p^5$

(D) $1 s^2 2 s^2 2 p^2$

Which of the following is the correct order of increasing electronegativity (Pauling's scale)?

<p>The electronic configurations of four elements, A, B, C, and D, are presented as follows:</p> <p><p>(A) $1s^2 2s^2 2p^3$</p></p> <p><p>(B) $1s^2 2s^2 2p^4$</p></p> <p><p>(C) $1s^2 2s^2 2p^5$</p></p> <p><p>(D) $1s^2 2s^2 2p^2$</p></p> <p>To determine the correct order of increasing electronegativity according to Pauling's scale, analyze the elements as follows:</p> <p><p>Nitrogen ($1s^2 2s^2 2p^3$): Electronegativity = 3.0</p></p> <p><p>Oxygen ($1s^2 2s^2 2p^4$): Electronegativity = 3.5</p></p> <p><p>Fluorine ($1s^2 2s^2 2p^5$): Electronegativity = 4.0</p></p> <p><p>Carbon ($1s^2 2s^2 2p^2$): Electronegativity = 2.55</p></p> <p>The correct order of increasing electronegativity is:</p> <p>Carbon (D) &lt; Nitrogen (A) &lt; Oxygen (B) &lt; Fluorine (C)</p>