The first ionization energy (in kJ/mol) of Na, Mg, Al and Si respectively, are :
Solution
Elecronic configuration of Na = [Ne] 3s<sup>1</sup>
<br>Mg = [Ne] 3s<sup>2</sup>
<br>Al = [Ne] 3s<sup>2</sup>3p<sup>1</sup>
<br>Si = [Ne] 3s<sup>2</sup>3p<sup>2</sup>
<br><br>Correct order is :
<br><br>Na $<$ Al $<$ Mg $<$ Si
About this question
Subject: Chemistry · Chapter: Periodic Table and Periodicity · Topic: Periodic Trends
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