The correct order of the first ionization enthalpy is
Solution
<p>I. $\mathrm{E}_1$ of $\mathrm{TI}=589 \mathrm{~kJ} / \mathrm{mol}$</p>
<p>I. $\mathrm{E}_1$ of $\mathrm{Ga}=579 \mathrm{~kJ} / \mathrm{mol}$</p>
<p>I. $\mathrm{E_1}$ of $\mathrm{Al}=577 \mathrm{~kJ} / \mathrm{mol}$</p>
About this question
Subject: Chemistry · Chapter: Periodic Table and Periodicity · Topic: Periodic Trends
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