Match List - I with List - II.
| List I Electronic configuration |
List II ${\Delta _i}H$ in kJ $mo{l^{ - 1}}$ |
||
|---|---|---|---|
| (a) | $1{s^2}2{s^2}$ | (i) | 801 |
| (b) | $1{s^2}2{s^2}2{p^4}$ | (ii) | 899 |
| (c) | $1{s^2}2{s^2}2{p^3}$ | (iii) | 1314 |
| (d) | $1{s^2}2{s^2}2{p^1}$ | (iv) | 1402 |
Choose the most appropriate answer from the options given below :
Solution
(a) 1s<sup>2</sup> 2s<sup>2</sup> $\to$ Be<br><br>
(b) 1s<sup>2</sup> 2s<sup>2</sup> 2p<sup>4</sup> $\to$ O<br><br>
(c) 1s<sup>2</sup> 2s<sup>2</sup> 2p3 $\to$ N<br><br>
(d) 1s<sup>2</sup> 2s<sup>2</sup> 2p<sup>1</sup> $\to$ B<br><br>
The ionization enthalpy order is<br><br>
B < Be < O < N<br><br>
Be has more IE compared to B due to extra
stability & N has more IE compared to oxygen
due to extra stability.<br><br>
Hence, N $\to$ 1402 kJ/mol<br><br>
O $\to$ 1314 kJ/mol<br><br>
B $\to$ 801 kJ/mol<br><br>
Be $\to$ 899 kJ/mol
About this question
Subject: Chemistry · Chapter: Periodic Table and Periodicity · Topic: Periodic Trends
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