The first ionization enthalpy of Na, Mg and Si, respectively, are : 496, 737 and $786 \mathrm{~kJ} \mathrm{~mol}^{-1}$. The first ionization enthalpy ($\mathrm{kJ} \,\mathrm{mol}^{-1}$) of $\mathrm{Al}$ is :
Solution
I.E. $\mathrm{Na}<\mathrm{Al}<\mathrm{Mg}<\mathrm{Si}$
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$\because 496<$ I.E. (Al) $<737$
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Option (C), matches the condition <br/><br/>i.e. I.E. $(\mathrm{Al})=577 \mathrm{~kJ} \mathrm{~mol}^{-1}$
About this question
Subject: Chemistry · Chapter: Periodic Table and Periodicity · Topic: Periodic Trends
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