The number of possible stereoisomers for a molecule with two chiral centres is $x$.
Answer (integer)
4
Solution
For n chiral centres, maximum stereoisomers = 2ⁿ. For 2 chiral centres: 2² = 4 (RR, SS, RS, SR — enantiomers + diastereomers).
About this question
Subject: Chemistry · Chapter: Organic Chemistry: Basic Principles · Topic: Isomerism
This question is part of PrepWiser's free JEE Main question bank. 20 more solved questions on Organic Chemistry: Basic Principles are available — start with the harder ones if your accuracy is >70%.