Easy INTEGER +4 / -1 PYQ · JEE Mains 2021

If the conductivity of mercury at 0$^\circ$C is 1.07 $\times$ 106 S m$-$1 and the resistance of a cell containing mercury is 0.243$\Omega$, then the cell constant of the cell is x $\times$ 104 m$-$1. The value of x is ____________. (Nearest integer)

Answer (integer) 26

Solution

Conductance (G) is reciprocal of resistance (R)<br/><br/>$R = {1 \over G}$ or $G = {1 \over R} = {1 \over {0.243\Omega }} = 4.115{\Omega ^{ - 1}}$<br/><br/>Relation between conductance (G),<br/><br/>conductivity ($\kappa$) and cell constant $\left( {{l \over A}} \right)$ is given as<br/><br/>$\kappa = {{Gl} \over A}$<br/><br/>$$ \Rightarrow {l \over A} = {\kappa \over G} = {{1.07 \times {{10}^6}S{m^{ - 1}}} \over {4.115{\Omega ^{ - 1}}}} = 26 \times {10^4}{m^{ - 1}} \Rightarrow x = 26$$

About this question

Subject: Chemistry · Chapter: Electrochemistry · Topic: Electrochemical Cells

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