Molar ionic conductivities of divalent cation and anion are $57 \mathrm{~S~cm}^2 \mathrm{~mol}^{-1}$ and $73 \mathrm{~S~cm}^2 \mathrm{~mol}^{-1}$ respectively. The molar conductivity of solution of an electrolyte with the above cation and anion will be:
Solution
<p>The compound with divalent cation $\left(\mathrm{A}^{2+}\right)$ and anion $\left(B^{2-}\right)$ will be $A B$.</p>
<p>Molar conductivity of its solution will be</p>
<p>$57+73=130 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$</p>
About this question
Subject: Chemistry · Chapter: Electrochemistry · Topic: Electrochemical Cells
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