Easy MCQ +4 / -1 PYQ · JEE Mains 2024

Molar ionic conductivities of divalent cation and anion are $57 \mathrm{~S~cm}^2 \mathrm{~mol}^{-1}$ and $73 \mathrm{~S~cm}^2 \mathrm{~mol}^{-1}$ respectively. The molar conductivity of solution of an electrolyte with the above cation and anion will be:

  1. A $187 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$
  2. B $260 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$
  3. C $65 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$
  4. D $130 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$ Correct answer

Solution

<p>The compound with divalent cation $\left(\mathrm{A}^{2+}\right)$ and anion $\left(B^{2-}\right)$ will be $A B$.</p> <p>Molar conductivity of its solution will be</p> <p>$57+73=130 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$</p>

About this question

Subject: Chemistry · Chapter: Electrochemistry · Topic: Electrochemical Cells

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