A KCl solution of conductivity 0.14 S m$-$1 shows a resistance of 4.19$\Omega$ in a conductivity cell. If the same cell is filled with an HCl solution, the resistance drops to 1.03$\Omega$. The conductivity of the HCl solution is ____________ $\times$ 10$-$2 S m$-$1. (Round off to the Nearest Integer).
Answer (integer)
57
Solution
For KCl solution,<br><br>$$R = \left( {{1 \over K}} \right)\left( {{l \over A}} \right) \Rightarrow {l \over A} = R \times K = 4.19 \times 0.14$$<br><br>= 0.58<br><br>For HCl solution,<br><br>$R = \left( {{1 \over K}} \right)\left( {{l \over A}} \right)$<br><br>$$ \Rightarrow K = {{(l/A)} \over R} = {{0.58} \over {1.03}} = 0.56 = 56 \times {10^{ - 2}}$$ Sm<sup>$-$1</sup>
About this question
Subject: Chemistry · Chapter: Electrochemistry · Topic: Electrochemical Cells
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