"A 5.0 m mol dm$-$3 aqueous solution of KCl has a conductance of 0.55 mS when measured in a cell of cell constant 1.3 cm$-$1. The molar conductivity of this solution is ___________ mSm2 mol$-$1. (Round off to the Nearest Integer)."

Question

Accepted Answer

"Conductance = ${{Conductivity} \over {Cell\,cons\tan t}}$

$\therefore$ Conductivity = 0.55 $\times$ 10^$-$3 $\times$ 1.3 S cm^$-$1

Molar conductivity = ${{Conductivity\,(S\,c{m^{ - 1}}) \times 1000} \over {Molarity\,(mol/L)}}$

$$ = {{0.55 \times {{10}^{ - 3}} \times 1.3 \times 100} \over {5 \times {{10}^{ - 3}}}}$$

= 143 S cm² mol^$-$1

= 14.3 mS m² mol^$-$1

$\approx$ 14 mS m² mol^$-$1"

A 5.0 m mol dm^$-$3 aqueous solution of KCl has a conductance of 0.55 mS when measured in a cell of cell constant 1.3 cm^$-$1. The molar conductivity of this solution is ___________ mSm² mol^$-$1. (Round off to the Nearest Integer).

Solution

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A 5.0 m mol dm$-$3 aqueous solution of KCl has a conductance of 0.55 mS when measured in a cell of cell constant 1.3 cm$-$1. The molar conductivity of this solution is ___________ mSm2 mol$-$1. (Round off to the Nearest Integer).

Solution

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A 5.0 m mol dm^$-$3 aqueous solution of KCl has a conductance of 0.55 mS when measured in a cell of cell constant 1.3 cm^$-$1. The molar conductivity of this solution is ___________ mSm² mol^$-$1. (Round off to the Nearest Integer).