Given that the standard potentials (Eo) of Cu2+/Cu and Cu+/Cu are 0.34 V and 0.522 V respectively, the Eo of Cu2+/Cu+ :
Solution
Cu<sup>+2</sup> + 2e<sup>–</sup> $\to$ Cu E<sup>o</sup> = 0.34 V ....(1)
<br><br>Cu<sup>+</sup> + e<sup>–</sup> $\to$Cu E<sup>o</sup> = 0.522 V
<br><br>Cu $\to$ Cu<sup>+</sup> + e<sup>–</sup> E<sup>o</sup> = -0.522 V ...(2)
<br><br>By adding (1) and (2) we get,
<br><br>Cu<sup>+2</sup> + e<sup>–</sup> $\to$ Cu<sup>+</sup>
<br><br>E<sup>o</sup><sub>cell</sub> = ${{0.34 \times 2 + 1 \times \left( { - 0.522} \right)} \over 1}$ = 0.158 V
About this question
Subject: Chemistry · Chapter: Electrochemistry · Topic: Electrochemical Cells
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